9y^2=20y

Solution for 9y^2=20y equation:

9y^2=20y

We move all terms to the left:

9y^2-(20y)=0

a = 9; b = -20; c = 0;
Δ = b2-4ac
Δ = -202-4·9·0
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{400}=20$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-20}{2*9}=\frac{0}{18}
=0
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+20}{2*9}=\frac{40}{18}
=2+2/9
$